(2x^2-3)+(3x^2+4)=0

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Solution for (2x^2-3)+(3x^2+4)=0 equation:


Simplifying
(2x2 + -3) + (3x2 + 4) = 0

Reorder the terms:
(-3 + 2x2) + (3x2 + 4) = 0

Remove parenthesis around (-3 + 2x2)
-3 + 2x2 + (3x2 + 4) = 0

Reorder the terms:
-3 + 2x2 + (4 + 3x2) = 0

Remove parenthesis around (4 + 3x2)
-3 + 2x2 + 4 + 3x2 = 0

Reorder the terms:
-3 + 4 + 2x2 + 3x2 = 0

Combine like terms: -3 + 4 = 1
1 + 2x2 + 3x2 = 0

Combine like terms: 2x2 + 3x2 = 5x2
1 + 5x2 = 0

Solving
1 + 5x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 5x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 5x2 = 0 + -1
5x2 = 0 + -1

Combine like terms: 0 + -1 = -1
5x2 = -1

Divide each side by '5'.
x2 = -0.2

Simplifying
x2 = -0.2

Reorder the terms:
0.2 + x2 = -0.2 + 0.2

Combine like terms: -0.2 + 0.2 = 0.0
0.2 + x2 = 0.0

The solution to this equation could not be determined.

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